x^2+4x^2=153

Solution for x^2+4x^2=153 equation:

x^2+4x^2=153

We move all terms to the left:

x^2+4x^2-(153)=0

We add all the numbers together, and all the variables

5x^2-153=0

a = 5; b = 0; c = -153;
Δ = b2-4ac
Δ = 02-4·5·(-153)
Δ = 3060
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3060}=\sqrt{36*85}=\sqrt{36}*\sqrt{85}=6\sqrt{85}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{85}}{2*5}=\frac{0-6\sqrt{85}}{10}
=-\frac{6\sqrt{85}}{10}
=-\frac{3\sqrt{85}}{5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{85}}{2*5}=\frac{0+6\sqrt{85}}{10}
=\frac{6\sqrt{85}}{10}
=\frac{3\sqrt{85}}{5}
$